(2x-1)(3x^2+x-5)=

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Solution for (2x-1)(3x^2+x-5)= equation: 


Simplifying
(2x + -1)(3x2 + x + -5) = 0

Reorder the terms:
(-1 + 2x)(3x2 + x + -5) = 0

Reorder the terms:
(-1 + 2x)(-5 + x + 3x2) = 0

Multiply (-1 + 2x) * (-5 + x + 3x2)
(-1(-5 + x + 3x2) + 2x * (-5 + x + 3x2)) = 0
((-5 * -1 + x * -1 + 3x2 * -1) + 2x * (-5 + x + 3x2)) = 0
((5 + -1x + -3x2) + 2x * (-5 + x + 3x2)) = 0
(5 + -1x + -3x2 + (-5 * 2x + x * 2x + 3x2 * 2x)) = 0
(5 + -1x + -3x2 + (-10x + 2x2 + 6x3)) = 0

Reorder the terms:
(5 + -1x + -10x + -3x2 + 2x2 + 6x3) = 0

Combine like terms: -1x + -10x = -11x
(5 + -11x + -3x2 + 2x2 + 6x3) = 0

Combine like terms: -3x2 + 2x2 = -1x2
(5 + -11x + -1x2 + 6x3) = 0

Solving
5 + -11x + -1x2 + 6x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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